Average marks of N students - C Program

 

In this C program we are calculating the total and average/percentage of marks of N students using Arrays.

Arrays are the collection of elements of same type of data. Arrays can store only one type of data like int, float, char, double.

Description:

i – Loop control variable.
n – Number of students.
m1,m2 and m3 – Array which stores the marks of 3 subjects of ‘n’ students.
total – Array which stores the sum of marks of 3 subjects.
average – Array which stores the total/3 : average marks/percentage.
Input : Number of students, Marks of 3 subjects of ‘n’ students.
Output : Average/Percentage of marks, Result of student

Algorithm to calculate total & average/percentage of marks of N students:

STEP 1: START
STEP 2: READ the number of students whose average needs to be calculated
              READ n
STEP 3: READ the marks of 3 subjects of ‘n’ students into array
              LOOP from i = 0 to n
              READ m1 m2 m3
STEP 4: CALCULATE the total marks and average marks of ‘n’ students
             LOOP from i = 0 to n
             total(i) = m1(i)+m2(i)+m3(i) average(i) = total(i)/3
STEP 5: PRINT the average marks and PASS/FAIL
              PRINT “average”  and “PASS/FAIL”
STEP 6: END

C Program to find total & average/percentage of marks of N students:

#include<stdio.h>
#include<conio.h>
void main()
{
    int n, a[25], i, total[20],m1[20],m2[20],m3[20];
    float average[20];
    printf("Enter number of students: ");
    scanf("%d",&n);
    for(i=0;i<n;i++)
    {
        printf("Enter the marks of 3 subjects of student %d: ",i+1);
        scanf("%d %d %d",&m1[i],&m2[i],&m3[i]);
    }
    for(i=0;i<3;i++)
    {
        total[i]=m1[i]+m2[i]+m3[i];
        average[i]=(float)total[i]/3;
    }
    for(i=0;i<n;i++)
    {
        printf("\nAverage/percentage marks of student %d is: %f",i+1,average[i]);
        if(average[i]>=35)
            printf("\nStudent is PASS");
        else
            printf("\nStudent is FAIL");
    }
    getch();
}

Output 1:

Enter number of students: 3
Enter the marks of 3 subjects of student 1: 89 76 94
Enter the marks of 3 subjects of student 2: 32 89 11
Enter the marks of 3 subjects of student 3: 22 36 33
Average/percentage marks of student 1 is: 86.333336
Student is PASS
Average/percentage marks of student 2 is: 44.000000
Student is PASS
Average/percentage marks of student 3 is: 30.333334
Student is FAIL

Output 2:

Enter number of students: 2
Enter the marks of 3 subjects of student 1: 88 55 98
Enter the marks of 3 subjects of student 2: 23 43 24
Average/percentage marks of student 1 is: 80.333336
Student is PASS
Average/percentage marks of student 2 is: 30.000000
Student is FAIL

QUIZ:

1] Array stores data from index.

1. zero (0)
2. one (1)
3. any index
4. – 1

2] Arrays are

1. 1-D
2. 2-D
3. Multidimensional
4. All

3] Array index can be negative.

1. TRUE
2. FALSE